A crane operator plans to lift a gross load of 26,300 lbs. What is the minimum number of parts of line required if the line pull of the crane base is 6,000 lbs?

To determine the minimum number of parts of line required for a crane to safely lift a gross load of 26,300 lbs, we must consider the line pull capacity of the crane's base, which is 6,000 lbs. The relationship between the load weight and the number of parts of line is based on the fact that the weight supported by the crane is distributed across the parts of line.

The formula used to calculate the number of parts of line needed is:

Number of Parts of Line = Load Weight / Line Pull Capacity

Using the gross load weight of 26,300 lbs and the crane base line pull of 6,000 lbs, we perform the calculation as follows:

Number of Parts of Line = 26,300 lbs / 6,000 lbs = 4.38

Since the number of parts of line must be a whole number, we round up to the nearest whole number to ensure that the crane can safely handle the load.

Consequently, a minimum of five parts of line is required for the crane to safely lift the 26,300 lbs. This ensures that the load is well within the crane's operational limits and minimizes the risk of overload.

Thus, choosing the minimum number of parts as five provides